Sujet : Re: Does the number of nines increase?
De : james.g.burns (at) *nospam* att.net (Jim Burns)
Groupes : sci.mathDate : 08. Jul 2024, 18:33:04
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <b8d894a3-1c18-4fd6-a01a-4a40d190df80@att.net>
References : 1 2 3 4 5 6 7 8 9 10 11
User-Agent : Mozilla Thunderbird
On 7/8/2024 9:49 AM, WM wrote:
Le 08/07/2024 à 01:57, Jim Burns a écrit :
On 7/7/2024 4:04 PM, WM wrote:
The question is only this:
Are there more than one unit fractions in
the point where NUF(x) changes from 0 to more,
or is there only one unit fraction?
>
The complete distribution of unit fractions,
>
does not answer this question.
...determines which things you are asking about.
Are you asking about things for which
each nonempty set holds a rightmost element (nearest 1)?
Are you asking about things for which
each u (including 1) has ⅟(1+⅟u) next.thing.to.the.left?
Are you asking about things for which
each v (excluding 1) has ⅟(-1+⅟v) next.thing.to.the.right?
If your answers are yes, yes, and yes,
then, whatever the things are called,
the answer to your question is the third option: none.
/ If there is a point x > 0: NUF(x) < ℵ₀
| then there is a leftmost unit.fraction β in (0,x]
| and unit fraction u₂ᵦ < 2⋅β not.leftmost
| and unit.fraction ¼⋅u₂ᵦ < ½⋅β < β
| to the left of leftmost unit.fraction β
\ Contradiction.
There is no point x > 0: NUF(x) < ℵ₀
There is no point x < 0: NUF(x) > 0
NUF(x) changes "at" 0.
And,
if any of the three answers is no,
then you're asking about something else.
Maybe some day you'll say what you're asking about.
NUF(0) = 0
NUF(x) changes at 0
There is no unit fraction at 0
>
Therefore it does not change at 0.
Functions do not change at single points.
A change needs be _with respect to_ something, and
the value at a point with respect to itself
is unchanging.
Consider the function
NP(x) = |{.01,.02,.03,…,1.00}∩(0,x]|
NP(.005) = 0
NP(.015) = 1
NP(x) changes between .005 and .015
for 0<β<.01
NP(.01-β) = 0
NP(.01+β) = 1
NP(x) changes between .01-β and .01+β
NP(.01) = NP(.01) is unchanging.
Consider once more the function
NUF(x) = |⅟ℕ∩(0,x]|
for each x
NUF(x) = NUF(x) is unchanging.
for 0<β
NUF(0-β) = 0
NUF(0+β) = ℵ₀
NUF(x) changes between 0-β and 0+β
for 0<β
NUF(0+β) = ℵ₀
because, otherwise,
a unit fraction u₂ᵦ exists such that
¼⋅u₂ᵦ is NOT a unit fraction.