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Am Wed, 17 Jul 2024 15:08:30 +0000 schrieb WM:No, ℵo finite intervals do not fit between [0, 1] and (0, 1]. The sign function fits.Le 17/07/2024 à 16:56, Moebius a écrit :The same as the sign function.Am 17.07.2024 um 16:43 schrieb WM:Thema verfehlt. The question is: How does NUF(x) increase from 0 toCan you explain how NUF(x) can [jump] from 0 [at x = 0] to [aleph_0]Yes, of course: For each and every x e IR, x > 0 there are
[at any]
point x [> 0] although all unit fractions are separated by finite
distances [...]
countably-infinitely many unit fractions which are <= x. (Hint: No
first one.)
more? There is a point where NUF is 0 and then it increases. How?
There simply is no such "point", asThey remain finite in every case.
there is no least positive number. The distances between unit
fractions get infinitely small.
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