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Le 17/07/2024 à 19:01, joes a écrit :Where do you get this requirement from?Am Wed, 17 Jul 2024 15:08:30 +0000 schrieb WM:No, ℵo finite intervals do not fit between [0, 1] and (0, 1]. The signLe 17/07/2024 à 16:56, Moebius a écrit :The same as the sign function.Am 17.07.2024 um 16:43 schrieb WM:Thema verfehlt. The question is: How does NUF(x) increase from 0 toCan you explain how NUF(x) can [jump] from 0 [at x = 0] to [aleph_0]Yes, of course: For each and every x e IR, x > 0 there are
[at any]
point x [> 0] although all unit fractions are separated by finite
distances [...]
countably-infinitely many unit fractions which are <= x. (Hint: No
first one.)
more? There is a point where NUF is 0 and then it increases. How?
function fits.
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