Liste des Groupes | Revenir à s math |
Am Wed, 17 Jul 2024 17:17:54 +0000 schrieb WM:Le 17/07/2024 à 19:01, joes a écrit :Am Wed, 17 Jul 2024 15:08:30 +0000 schrieb WM:No, ℵo finite intervals do not fit between [0, 1] and (0, 1]. The signLe 17/07/2024 à 16:56, Moebius a écrit :The same as the sign function.Am 17.07.2024 um 16:43 schrieb WM:Thema verfehlt. The question is: How does NUF(x) increase from 0 toCan you explain how NUF(x) can [jump] from 0 [at x = 0] to [aleph_0]Yes, of course: For each and every x e IR, x > 0 there are
[at any]
point x [> 0] although all unit fractions are separated by finite
distances [...]
countably-infinitely many unit fractions which are <= x. (Hint: No
first one.)
more? There is a point where NUF is 0 and then it increases. How?
function fits.
Where do you get this requirement from?ℵo unit fractions occupy ℵo finite intervals.
Consider the sign function times infinity.The sign function can change from point 0 to all points of the interval (0, oo) without exception. NUF needs some of these points to acquire ℵo unit fractions.
Les messages affichés proviennent d'usenet.