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On 8/16/2024 1:00 PM, WM wrote:
That violates ∀n ∈ ℕ: 1/n - 1/(n+1) > 0 .Start from x = 0.Start from x = 0
The increase cannot be more than 1.
∀n ∈ ℕ: 1/n - 1/(n+1) > 0
The increase cannot be less than 2
∀ᴿx > 0: x > ⅟nₓ > ⅟(nₓ+1)That holds only for definable numbers.
nₓ = ⌊1+⅟x⌋
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