Sujet : Re: Replacement of Cardinality
De : invalid (at) *nospam* example.invalid (Moebius)
Groupes : sci.mathDate : 28. Aug 2024, 14:05:04
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <van7a1$3fpfi$3@dont-email.me>
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Am 28.08.2024 um 06:23 schrieb joes:
Am Tue, 27 Aug 2024 19:26:25 +0000 schrieb WM:
Le 25/08/2024 à 23:18, Jim Burns a écrit :
>
Therefore, there is no ω-1,
*sigh*
Therefore there is no ordinal number o such that o + 1 = ω.
If the set of ordinal numbers is complete, then ω-1 precedes ω - by
definition.
How does it go again?
WM defines "complete" comcerning (sets of) ordinal numbers the following way:
A set of ordinals is /complete/ iff each and every ordinal
in the set (except 0) has an immediate predecessor (which
precedes it).
Simple as that.
In this sense, {0, 1, 2, 3, ... ω} is not (Mückenheim) complete.
Though clearly no ordinal between 0 and ω is "missing" - LOL. :-)
Hint: ~Eo e ORD: An e IN: n < o < ω.
Hence the term "complete" as defined by Mückenheim is quite "misleading" (to say the least).
We'd better define:
A set of ordinals is /Mückenheim complete/ iff each and every
ordinal in the set (except 0) has an immediate predecessor
(which precedes it).
Theorem: {0, 1, 2, 3, ... ω} is not Mückenheim complete. :-)
Though it's not clear what's missing here. :-)