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on 8/29/2024, WM supposed :Of course they are visible. The collection of visible numbers is potentially infinite. It reaches as far as induction reaches. But *if actual infinity is existing*, then almost all natural numbers are not reached by induction.Le 29/08/2024 à 13:00, FromTheRafters a écrit :What about n+n if n is visible? or n+1?
>He seems to think that n being some undisclosed (dark) natural number means that n+1 is merely another undisclosed (dark) natural number and you cannot pair (thinking of matching,>
No. If n is a visible nabtuarl number, then also n^n^n is also a visible natural number. That is potential infinity.
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