Sujet : Re: How many different unit fractions are lessorequal than all unit fractions?
De : james.g.burns (at) *nospam* att.net (Jim Burns)
Groupes : sci.mathDate : 04. Sep 2024, 22:26:45
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <69325e33-6b9a-4c2f-a0e3-25508d41b114@att.net>
References : 1 2 3
User-Agent : Mozilla Thunderbird
On 9/4/2024 4:23 PM, WM wrote:
On 04.09.2024 20:08, Jim Burns wrote:
On 9/2/2024 1:07 PM, WM wrote:
How many different unit fractions are
lessorequal than all unit fractions?
The correct answer is: one unit fraction.
>
Another answer is that
no unit fraction is
lessorequal than all unit fractions.
>
Then NUF(x) will never leave the value 0.
>
Not all sets are finite.
>
But all different unit fractions are different,
i.e., they sit at different positive x.
Around each of ℵ₀.many visibleᵂᴹ ⅟k,
mark a gap of length g/2ᵏ
Gap length g/2ᵏ decreases exponentially faster than
gap distance ⅟k-⅟(k+1)
If gaps do not overlap initially,
then they do not overlap ever.
⎛ Gₖ = g/2+g/4+g/8+...+g/2ᵏ
⎜
⎜ ½⋅(g+Gₖ) =
⎜ ½⋅(g+g/2+g/4+g/8+...+g/2ᵏ) =
⎜ g/2+g/4+g/8+...+g/2ᵏ+g/2ᵏ⁺¹ =
⎜ Gₖ+g/2ᵏ⁺¹
⎜
⎜ ½⋅(g+Gₖ) = Gₖ+g/2ᵏ⁺¹
⎝ Gₖ = g-g/2ᵏ < g
For visibleᵂᴹ unit.fraction ⅟j, let g = ½⋅⅟j²
ℵ₀.many visibleᵂᴹ unit.fractions ⅟ℕᴰᴱꟳ and the gaps g/2ᵏ
fit between 0 and ⅟j
But all different unit fractions are different,
i.e., they sit at different positive x.
Yes,
each two sit at two points,
because ∀n ∈ ℕ: ⅟n-⅟(n+1) > 0
Therefore only one can sit closest to zero.
No,
each sits not.closest to zero,
because ∀n ∈ ℕ: ⅟n-⅟(n+1) > 0