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On 07.09.2024 04:01, Richard Damon wrote:Then the idea that NUF(x) "increases by one" at the values of "unit fractions" must be dropped.On 9/6/24 8:12 AM, WM wrote:This idea must be dropped.On 05.09.2024 21:57, Jim Burns wrote:>On 9/5/2024 9:59 AM, WM wrote:>>NUF(x) increases from 0 to more.>
...at 0.
No. NUF(x) counts the unit fractions between 0 and x. Between 0 and 0 there is no unit fraction. NUF(0) = 0.
But it CAN'T for the values of x that are finite, as for ANY finite number, there is an infinite number of unit factions below it, so it can't ever have a finite value for any finite x.
Regards, WM
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