Sujet : Re: How many different unit fractions are lessorequal than all unit fractions?
De : james.g.burns (at) *nospam* att.net (Jim Burns)
Groupes : sci.mathDate : 09. Sep 2024, 20:05:36
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <2343718c-22a8-46d4-b713-5c0cfd951c87@att.net>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
User-Agent : Mozilla Thunderbird
On 9/9/2024 6:39 AM, WM wrote:
On 08.09.2024 22:21, Jim Burns wrote:
There aren't two.
There isn't one.
There is no smallest unit fraction.
>
Then there is no unit fraction.
⎛ Each real number > 0 is a rational > 0 or
⎜ between sides of a split of rationals > 0
⎜
⎜ Each rational > 0 is the ratio of
⎜ two integers > 0
⎜
⎜ Each nonempty set S of integers > 0 holds
⎜ minimum.S
⎜ Each integer > 0 has a successor.integer > 0 (+1)
⎜ Each integer > 0 has a predecessor.integer > 0 (-1)
⎝ except the minimum integer > 0 (1).
Those are the points we are talking about.
If you aren't talking about those,
what you say is irrelevant _to those_
If you are talking about those,
then, no,
-- there are unit fractions,
-- each real number > 0 is undercut by ⅟k
where ⅟k is countable.down.to from ⅟1
-- for each x > 0, for each j countable.up.to from 1
there are more.than.j unit.fractions in (0,x)
-- there is no first (smallest) unit fraction, and
-- there aren't fewer.than.ℵ₀ unit.fractions in (0,x)
ℵo unit fractions cannot exist without
1, 2, 3, ... unit fractions before.
Each unit.fraction has 1,2,3,... unit.fraction before.
It is incorrect (it is a quantifier shift)
to conclude from that correct claim
that
🛇 there are 1,2,3,... unit.fractions before each