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On 25.09.2024 18:39, joes wrote:Which means for any 1/n, there exist a 1/(n+1) that is smaller than it, and thus there is no smallest 1/n.Am Wed, 25 Sep 2024 17:51:56 +0200 schrieb WM:By our mathematical knowledge about ∀n ∈ ℕ: 1/n - 1/(n+1) > 0NUF(x) distinguishes all points.How does it distinguish dark points?
Nope. "Next To" isn't a property of that set.There is a unit fraction next to 0.NUF increases. At no point it can increase by more than 1.Right, and there is no point "next to" 0
Right, and thus, for *ANY* 1/n, there exist a 1/(n+1) that will be smaller than it.∀n ∈ ℕ: 1/n - 1/(n+1) > 0Even if most mathematicians are far too stupid to understand this, IYou should try explaining it a different way.
will repeat it on and on, maybe that sometime some will get it.
is invincible.
Regards, WM
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