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On 01.10.2024 01:07, Richard Damon wrote:Then it can't be.On 9/30/24 2:54 PM, WM wrote:Wrong because it cannot start with ℵo.NUF(0) = 0 and NUF(1) = ℵo. ∀n ∈ ℕ: 1/n - 1/(n+1) > 0 shows that at no point x NUF can increase by more than one step 1. It is fact with your set too. I am not responsible. I only made the discovery.>
Actually, it shows that at no point CAN it increase by 1.
No, just that there isn't a point for it to start counting at>If NUF is ℵo at all x > 0 then it must count ℵo unit fractions at 0. Wrong.
For any finite number x, NUF(x) will be Aleph_0, and Aleph_0 when you attempt to "increment" it, doesn't change.
No presumption was made. Just proof.>Wrong presupposition.
Since there is no finite value of x where NUF(x) can be 1
Regards, WM
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