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Am Wed, 09 Oct 2024 11:47:57 +0200 schrieb WM:Of course.On 08.10.2024 21:23, joes wrote:Such an intersection is itself part of the sequence.Am Tue, 08 Oct 2024 17:30:19 +0200 schrieb WM:I am talking about such endsegments. Their intersection is infinite.On 08.10.2024 15:26, joes wrote:We are, again, not talking about an element of the sequence, which hasAm Tue, 08 Oct 2024 12:46:01 +0200 schrieb WM:>All endsegments which have infinitely many natural numbers.Because infinitely many natural numbers are contained. This is trueWhat does „they” refer to in the last sentence?
for all infinite sets of the function. Therefore they cannot have
lost all numbers.
a natural index, contains infinitely many successors and is missing a
finite number of predecessors.
Because every n has become an index and then is lost.Why?What we are talking about is the, pardon,The limit-endsegment is empty.
limit of whatever function.
(Potentially in-)finitely many because the collection of indices is finite as long as an infinite set of numbers remains within the endsegments.The intersection is infinite because all infinite endsegments containAnd how many segments have been intersected?
the same infinite set. Some have lost more or less numbers but the core
remains infinite in all infinite endsegments.
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