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On 10/20/2024 3:40 AM, WM wrote:Every exchange is one and has to obey logic.On 20.10.2024 00:08, Jim Burns wrote:On 10/19/2024 2:28 PM, WM wrote:It is my claim that>The contradiction is independent of infinity.>
It is your claim that
infinitely.many exchanges in an infinite set
(vanishing Bob)
Every exchange is _one_ lossless exchange.
infinitely.many exchanges in an infinite set
can result in the loss of one of them.
1 is not infinite.
If it did not contain dark elements and in spite of that was complete, the same could be done there.It is nonsense like:A finite set can be ordered such that
∀n ∈ ℕ:
|{2, 4, 6, ..., 2n}|/|{1, 2, 3, 4, 5, 6, ..., 2n} = 1/2
but
|{2, 4, 6, ...}|/|{1, 2, 3, 4, 5, 6, ...} = 1.
each subset holds its top and bottom or is empty.
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