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On 20.10.2024 21:42, Jim Burns wrote:On 10/20/2024 3:24 PM, WM wrote:On 20.10.2024 20:20, Jim Burns wrote:On 10/20/2024 3:48 AM, WM wrote:On 20.10.2024 00:54, Jim Burns wrote:On 10/19/2024 2:19 PM, WM wrote:
We are not doubling a finite set. And 2n is in N for every n e N.Nevertheless 2n is not in the set {1, ..., n}.If n is countable.to from 0 then 2⋅n is countable.to from 0If all finites are doubled,But not in the mapped or multiplied range.
then all results are in the set of finites.
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