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On 22.10.2024 19:24, Jim Burns wrote:They should, otherwise the set was finite.On 10/22/2024 10:11 AM, WM wrote:These numbers did not belong to the set when it was multiplied."Creation" of these numbers is confusingly imagined to be creation ofThe numbers ARE fixed, there are just inf. many of them.All of them are multiplied by 2.
>The larger numbers have already all been "created".Not before multiplying them.
these numbers.
That includes the so-called "doubles", i.e. the even numbers.These numbers are described by axioms.By axiom also all numbers of the set are present and available to be
multiplied.Claims (axioms) are made which are true of each of these numbers,which can be multiplied.No number starts or stops being described by those axioms.The set is complete when its numbers are multiplied.In that sense,All numbers which are described are in the set when being multiplied.
no number starts or stops existing.
No number enters or exits the domain of discourse those axioms
describe.
Those doubles of doubles are in the original set as well.the numbers being.described.by.those.axioms == the numbers existingOf course. But all these are multiplied.
include, for each such number, double that number.
As are the doubles. N is not limited.The numbers and their doubles always were/will.beThey are existing when multiplied.
being.described.by.those.axioms always were/will.be existing.
Then we get no new numbers.We cannot perform supertasks like counting infinitely.many.But we can use all existing numbers, for instance for mappings.
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