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On 23.10.2024 13:37, Richard Damon wrote:But from 0 to 1 isn't an infinite distance, thus doubling can put you out of that bound, and we can find a specific definaable number where that happens. It has a finite value for the upper limit.On 10/22/24 12:12 PM, WM wrote:On 22.10.2024 18:03, Jim Burns wrote:It is infinite like the fractions between 0 and 1. When doubling we get even-numerator fractions, some of which greater the 1.>∀n ∈ ℕ: 2×n ∈ ℕ>
Not if all elements are existing before multiplication already.
IF not, then your actual infinity wasn't actually infinite
No, the end cannot be determined, because it isn't there.Your "actual infinity" seems to be just an unimaginably large value, not infinite, as your actual infinity has an end, it has an element without a successor, so it isn't the set it claims to be.The completed infinite cannot avoid to be complete. But it is infinite because the end cannot be determined because of the dark domain.
Regards, WM
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