Re: 2N=E

On 24.10.2024 15:59, joes wrote:

Am Thu, 24 Oct 2024 15:49:48 +0200 schrieb WM:

The possibility of always even greater ones in natural numbers proves
potential infinity.

You have it backwards. Surely the "complete" set should not be missing
those greater numbers that the "potential" set includes.

The potentially infinite set does not include them. Then they would be doubled too.

 

The greater ones have not been doubled because doubling of a complete
set creates a set covering a greater interval than covered before. (Half
the density implies twice the extension.)

They have also been doubled, along with their doubles. The powers of 2 and
their multiples form a subset of the naturals. The "size" of this set
is omega, and 2w=w, regardless of "reality".

The complete set covers an interval. When its density is reduced its extension is increased.
Regards, WM
Regards, WM