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On 25.10.2024 16:53, Jim Burns wrote:On 10/25/2024 7:42 AM, WM wrote:
For ordinals,>The whole interval (0, ω) is not finite,>
let alone the doubled interval.
⟦0,ω⦆ is the set of finite ordinals.
That is the definition of finite ordinal.
That is the definition of ω,
the first ordinal after all finite ordinals.
Correct so far.
>γ before ω: γ is finite.>
γ ∈ ⟦0,ω⦆ ⇒
∀β ∈ ⦅0,γ⟧: ∃α: α+1=β
>
ω before ξ: ξ is not finite.
ω ∈ ⦅0,ξ⟧ ⇒
¬∀β ∈ ⦅0,ξ⟧: ∃α: α+1=β
>
(Keep in mind that ¬∃α: α+1=ω )
That is wrong in complete infinity.
My infinity? You meanA better question is:>
why do you (WM) support it?
I support it in order to show that
your infinity is inconsistent.
Example:All unit fractions are reciprocals of
Almost all unit fractions
cannot be discerned by definable real numbers.
If they are existing,If it is existing,
they are indiscernible, i.e. dark.
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