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On 28.10.2024 15:07, FromTheRafters wrote:But since 1/n approaches zero, the spacing also approaches 0, and in fact faster then the numbers do, so the number of point you could put between 1/n and 0 and the spacing of 1/n and 1/(n+1) increases and the density goes to infinity.WM was thinking very hard :No. ∀n ∈ ℕ: 1/n - 1/(n+1) > 0 holds everywhere.The function NUF(x) = Number of Unit Fractions between 0 and x starts with 0 at 0.>
Followed by a discontinuity.
Which means that for even 1/n, there is a 1/(n+1) smaller than it, so no smallest 1/n.>It is mathematics:>> The reason is this: ∀n ∈ ℕ: 1/n - 1/(n+1) > 0.After NUF(x') = 1 it cannot change to NUF(x'') = 2 without pausing for an interval consisting of uncountably many real points.>
Your "Axiom of because I say so" is overworked.
So? The slope of NUF(x) over a range is proportial to the density of Unit Fractions in that area, since the density goes to infinity>It holds everywhere if mathematics holds everywhere.
Non sequitur. This is just the second part of your stepwise function.
As FINITE mathematics dictates it, which isn't applicable, since you have an infinite set.It doesn't have to happen step by step as you envision it.As mathematics dictates it.
You have confessed: In order to maintain actual infinity without dark numbers, you have to violate mathematics.But, you seem to have missed that the ancients proved that we can't have "actual infinity" as something we can directly handle as finite beings.
Regards, WM
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