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On 10/28/24 3:52 PM, WM wrote:There are no others on the real line.On 28.10.2024 12:21, Richard Damon wrote:Of course it can. just not at any finite value.On 10/28/24 6:36 AM, WM wrote:>>NUF increases by 1 or more, but more would violate mathematics.>
No, NUF(x) jumps from 0 to Aleph_0 in the domain of finite numbers, because there is no finite x where it has the value of 0.
It has the value 0 for all x =< 0. And it cannot jump by more than 1 at any point.
The it is dark.No, but the first steps happen at undefinable x.No, it happens at an x that isn't a finite number.
If you allow your NUF to accept infintesimal numbersNo, that is strongly forbidden.
Then it is dark bottom.No, the bottom is outside the set.>This infinity between 0 and (0, 1] is not what I can accept.>
Note, it isn't an "infinity between" it is that the "bottom" of (0, 1] doesn't exist as a definable point.
That is true. The bottom is dark.
Your "Darkness" is just your attempt to hide the problems with your logic.And your bottom outside the set is what?
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