Sujet : Re: 2N=E
De : richard (at) *nospam* damon-family.org (Richard Damon)
Groupes : sci.mathDate : 02. Nov 2024, 01:55:16
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <ea5b8e8fd08ae108c6a5ea83f448f9eeb889694e@i2pn2.org>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
User-Agent : Mozilla Thunderbird
On 11/1/24 6:30 AM, WM wrote:
On 01.11.2024 00:44, Richard Damon wrote:
On 10/31/24 4:27 PM, WM wrote:
Reducing the density increases the interval.
>
Nope, becuase there is a difference in nature between an interval of finite length, and an interval of infinite length.
If the complete interval is reduced in density then it is enlarged.
Complete sets remain of same size.
Regards, WM
Nope. because the "complete interval" has infinite length, and thus "density" in the finite sense isn't defined.
Yes, the set reamins of the same size, even though it has both the same number of members (since the result is 1:1 to the starting set0 and only half its number of members (since the odds were removed).
This is the nature of infinite sets, scaling by finite amounts don't change there size.