Re: 2N=E

On 11/2/24 6:29 AM, WM wrote:

On 02.11.2024 01:55, Richard Damon wrote:

On 11/1/24 1:28 PM, WM wrote:

if the meaning of invariable sets is used, then every doubling will produce numbers larger than all doubled elements of the set.

 

Nope. That is just your finite thinking getting in the way.

 That is not finite but complete thinking.

Nope, it is FINITE thinking, because completion intails letting it be what it is, and for the infinite, that means to go on forever and thus not have an end.
You just don't understand what you are thinking about.

>
You forget that the infinite set has no end,

 If all numbers are doubled, then larger numbers than existing are produced.

Nope, not if the set started infinite, then the larger numbers were already there,

 Regards, WM