Re: 2N=E

On 11/3/24 6:49 AM, WM wrote:

On 03.11.2024 01:17, Richard Damon wrote:

On 11/2/24 5:34 PM, WM wrote:

 

Remember, 2 times any Natural Number is a Natural Number, provable by mathematics.

 Every doubled interval gets larger. (0, ω)*2 = (0, ω*2).

Nope, as no element of (0, ω) when doubled exceeds ω, as all were finite, and twice a finite number is finite.
Note, you can't multiply an interval by a value, you double the elements of the interval. It might work for finite intervals, but not for infinite intervals.

 

Every interval (0, n) is finite because n is finite. But for dark numbers n this cannot be seen. The dark realm appears as infinite. It cannot be counted through.

>
And thus is not finite.

 Its numbers are finite as we see when a dark number becomes visible. ω is the first infinite number by definition. ω - 1 is finite but lies in the dark realm and therefore cannot be counted to. It appears as if it was infinite.
 

If a dark number can become visible, then it was never dark, and your set was never complete.
ω - 1 is NOT "finte" but undefined in the base mode of Trans-Finite Numbers, just as 0-1 isn't defined in the set of Numbers 0, 1, 2, ...
Your "Dark Numbers" are just the impossiblitlies your broken logic create to try to avoid showing their flaws.

Regards, WM