Re: 2N=E

Chris M. Thomasson submitted this idea :

On 11/4/2024 12:40 AM, FromTheRafters wrote:

Chris M. Thomasson laid this down on his screen :

On 11/3/2024 3:56 AM, WM wrote:

On 03.11.2024 09:50, joes wrote:

pparently you do think that there is a
natural n such that 2^n is infinite.

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If all naturals are there, then no further one is available.

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Sigh. There are infinite natural numbers, there is no last largest one.

 No, natural numbers are finite. The set of all of the natural numbers is infinite.

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Yeah. I meant they are with end aka no largest natural exists yet every
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any_natural + 1 = another_natural
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Why does WM seem to think that this might hold:
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any_natural + 1 = can_equal_a_strange_weirdo_dark_number_thing?
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[...]

He's got a huge mental block concerning pairing/bijection models. He thinks we have to know what the numbers are in order to claim a bijection exists between two equal sets. Further to that, he claims Peano, Cantor, and others were wrong to claim to have addressed all natural numbers or rational numbers and found a bijection.