Re: 2N=E

On 11/4/24 6:09 AM, WM wrote:

On 03.11.2024 22:21, Richard Damon wrote:

On 11/3/24 9:17 AM, WM wrote:
>

If a Natural Numbers are there, there is no further needed, as they go without end.

>
All are doubled. No remainings can absorb all products.
>

But there are, because they are infinite.
>
Your logic just doesn't work on infinite sets.

 My logic says all are there. Nobody knows whether I will double them again. If I decide to do so, then larger numbers are created.
 Regards, WM

Yes, *ALL* are there, without END, which your logic presmes there to be.
The assumption of the existance of the non-existance end breaks your logic and blows it up (with your mind) to smithereens, and the darkness you rtalk about is just an artifact of the void left by the explosion.
Yes, we know if you will double them again, as we started with the assumption that we double ALL the number, and any even number will be reached from doubling the number that is one half of it and will be doubled again.
We know this because we defined that is what we are doing.
If you try to think of it sequentially, as it seems you are doing, you can't ever do it, as it will require infinite sequential work, which a finite logic/mind can't do.
The larger numbers are not "created" as you assumed that you had the actual infinity where all were created, which creates a set with no upper bound in it. If you set has an upper bound, you didn't create the actual infinity, and just lied to yourself.