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Am 04.11.2024 um 17:50 schrieb Moebius:If they are equal, it is a multiset with one element with a multiplicity of three, and thus cardinality of three.Am 04.11.2024 um 12:33 schrieb Chris M. Thomasson:>
Infinite ways to represent 1:Right. {4 - 2 - 1, 3*2 - 5, 2 - 1, 3 - 2, 4 - 3, ...} = {1} (though FromTheAfter is too dumb to get that).
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1 = 4 - 2 - 1
1 = 3*2 - 5
1 = 1 + 1 - 1
1 = ...
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?
This idiot is convinced that "in any case" |{x, y, z}| = 3.
Actually,
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|{x, y, z}| = 3 iff x =/= y and x =/= z and y =/= z.
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