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On 11/6/24 10:15 AM, WM wrote:The will sum, but they will never sum to a so-called largest natural number... Right?On 06.11.2024 12:46, Richard Damon wrote:They will sum to Aleph_0, since there is a countable infinite number of them.On 11/5/24 11:45 AM, WM wrote:>On 05.11.2024 04:08, Richard Damon wrote:>On 11/4/24 12:11 PM, WM wrote:>On 04.11.2024 13:14, Richard Damon wrote:>On 11/4/24 6:07 AM, WM wrote:>>By induction you can prove the sum n(n+1)/2 for every initial segment 1+2+3+...+n. But not for all natural numbers.But all Natural Numbers can be defined.>
All defined numbers can be summed. Not all natural numbers can be summed.
Why not?
because most cannot be defined.
But they ARE defined.
Then sum all of them.
>
Regards, WM
Note, Addition on Natural Numbers is closed for FINITE sums (the sum of a finite number of numbers), not necessarily for infinite series of them.
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