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On 11.11.2024 19:23, Jim Burns wrote:On 11/11/2024 3:41 AM, WM wrote:
For that claim, I need>>>But it will never complete>
an infinite set of claims.
We do not need an infinite ๐๐ฒ๐พ๐๐ฒ๐ป๐ฐ๐ฒ of ๐ฐ๐น๐ฎ๐ถ๐บ๐ completed.
We do not want an infinite ๐๐ฒ๐พ๐๐ฒ๐ป๐ฐ๐ฒ of ๐ฐ๐น๐ฎ๐ถ๐บ๐ completed.
But you claim that
_all_ fractions are in bijection with
all natural numbers,
don't you?
Yes, I claim that.
For that claim you need an infinite set of claims.
It is one claim.This is one ๐ฐ๐น๐ฎ๐ถ๐บ:It is wrong.
โ All fractions are in bijection with
โ all natural numbers.
Which means what?>My intervals I(n) = [n - 1/10, n + 1/10]>
must be translated to all the midpoints
1/1, 1/2, 2/1, 1/3, 2/2, 3/1, 1/4, 2/3, 3/2, 4/1, 1/5,
2/4, 3/3, 4/2, 5/1, 1/6, 2/5, 3/4, 4/3, 5/2, 6/1, ...
if you want to contradict my claim.
Your ๐ฐ๐น๐ฎ๐ถ๐บ๐ start with "Sets change".
No, I claim that intervals can be translated.
(The set of intervals remains constantOur sets do not change.
in size and multitude.)
For every finite subset this is possible.Our sets do not change.
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