Sujet : Re: Incompleteness of Cantor's enumeration of the rational numbers (doubling-spaces)
De : james.g.burns (at) *nospam* att.net (Jim Burns)
Groupes : sci.mathDate : 12. Nov 2024, 21:03:14
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <d899eaaf-a9af-4c32-9a9b-eb959473a064@att.net>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
User-Agent : Mozilla Thunderbird
On 11/12/2024 1:06 PM, WM wrote:
On 12.11.2024 17:47, Jim Burns wrote:
[4-⅒,4+⅒] ≠ [1/3-⅒,1/3+⅒]
>
|[4-⅒,4+⅒]| = |[1/3-⅒,1/3+⅒]|
and only that is important for my argument.
Yes,
μ[4-⅒,4+⅒] = μ[1/3-⅒,1/3+⅒]
⎛ Also, |[0,1]| = |[0,2]|
⎝ so I think you mean 'measure', not 'cardinality'.
The value of a measure is defined to be
in the extended reals≥0.
μ⋃{ [n-⅒,n+⅒]:n∈ℕ⁺ } ∈ [0,+∞]
The extended reals≥0 are
the Archimedean reals≥0 [0,+∞)
plus one non.Archimedean point +∞
[0,+∞] = [0,+∞)∪{+∞}
The value of μ⋃{ [n-⅒,n+⅒]:n∈ℕ⁺ }
is not any Archimedean point, that is,
there is no finite m ∈ ℕ⁺ such that
μ⋃{ [n-⅒,n+⅒]:n∈ℕ⁺ } ≤ m
The value of μ⋃{ [n-⅒,n+⅒]:n∈ℕ⁺ }
is not Archimedean, so must be +∞
μ⋃{ [n-⅒,n+⅒]:n∈ℕ⁺ } = +∞
Also,
μ⋃{ [i/j-⅒,i/j+⅒]:i/j∈ℕ⁺/ℕ⁺ } = +∞
Or is it by accident that
you used n = 4 to cover q = 1/3?
1/1, 1/2, 2/1, 1/3, ...
>
No accident.
You got my point.
>
Then you will get my point, hopefully.
Your point is that
μ⋃{ [n-⅒,n+⅒]:n∈ℕ⁺ }
isn't in the extended reals.
I get it.
Getting it and
agreeing with your changes to our definitions,
changes which turn the discussion into gibberish,
are different.