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On 11/25/2024 7:11 AM, WM wrote:Consider the black hats at every 10 n and white hats at all other numbers n. It is possible to shift the black hats such that every interval (0, n] is completely covered by black hats. There is no first n discernible that cannot be covered by black hat. But the origin of each used black hat larger than n is now covered by a white hat. Without deleting all white hats it is not possible to cover all n by black hats. But deleting white hats is prohibited by logic. Exchanging can never delete one of the exchanged elements. Therefore we have here, like in all Cantor-pairings, the same impediment and further disussion is futile: You must deny logic. I do not.On 24.11.2024 19:16, Jim Burns wrote:On 11/24/2024 6:06 AM, WM wrote:On 24.11.2024 06:37, Jim Burns wrote:Thus>>Consider the set of natural numbers for which>
there are NOT enough hats.
It is dark.
It is not dark what we mean by 'natural number'.
A natural number is countable.to from.0
That is a definable number.
it is not dark that
what we mean by 'natural number' is
countable.to from.0 and is
what you call a definable number.
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