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On 25.11.2024 22:05, joes wrote:It is possible to change N to N\0.Am Mon, 25 Nov 2024 13:18:28 +0100 schrieb WM:It is impossible to add or to delete an element.What does that have to do with it?But there is no finite set with ALL natural numbers.ℕ is fixed, that means |ℕ| is fixed.
Like usual, you mess up with your qualifiers.
It is impossible to change |ℕ| by 1 or more.
Countably infinite.Yes, it is much.It has the same cardinality.It does.But the concept of 1/10th of an infinte set does not exist..Limit theory only works if the limit actually existsIf limits exist at all, then the limit of the sequence 1/10, 1/10,
1/10, ... does exist.
Cantor proved nothing more.Why not? Do it. Consider the black hats at every 10 n and white hats atWhy not just directly take N, made up of finite numbers?All are in the union of all finite sets.No, any given element is a member of a finite set, but you can't thenYou can get things that APPEAR to reach a limit, but actuallyBut if infinite sets do exist, then the set ℕ does exist, and all
don't.
its elements are members of finite intervals (0, n].
say that ALL are in such a set.
all other numbers n. It is possible to shift the black hats such that
every interval (0, n] is completely covered by black hats. There is no
first n discernible that cannot be covered by black hat.
But the originNot if you really coloured ALL n.
of each used black hat larger than n is now covered by a white hat.
Without deleting all white hats it is not possible to cover all n byAn infinite exchange can.
black hats. But deleting white hats is prohibited by logic. Exchanging
can never delete one of the exchanged elements.
Therefore we have here,Thanks for shutting up.
like in all Cantor-pairings, the same impediment and further disussion
is futile.
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