Re: Incompleteness of Cantor's enumeration of the rational numbers (extra-ordinary)

Am Thu, 28 Nov 2024 21:20:10 +0100 schrieb WM:

On 28.11.2024 20:28, FromTheRafters wrote:

WM used his keyboard to write :

On 28.11.2024 17:45, joes wrote:

Am Thu, 28 Nov 2024 11:39:05 +0100 schrieb WM:

>

A simpler arguments is this: All endsegments are in a decreasing
sequence.

There is no decrease, they are all infinite.

Every endsegment has one number less than its predecessor.
That is called decrease.

More like the subset relation. It is not a decrease in cardinality.

Of course not. Cardinality is nothing else than infinitely many.
But as long as infinitely many natnumbers have not left the endsegments,
they stay inside all of them.

That long you haven't taken all segments yet.

 

And many are the same for all endsegments.

Only for every finite number.