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WM expressed precisely :So, you have a deductive account that your inductive course completes?On 28.11.2024 20:28, FromTheRafters wrote:>WM used his keyboard to write :>On 28.11.2024 17:45, joes wrote:>Am Thu, 28 Nov 2024 11:39:05 +0100 schrieb WM:>>A simpler arguments is this: All endsegments are in a decreasingThere is no decrease, they are all infinite.
sequence.
Every endsegment has one number less than its predecessor.
That is called decrease.
More like the subset relation. It is not a decrease in cardinality.
Of course not. Cardinality is nothing else than infinitely many.
Wrong, it is also 'number of elements' for finite sets.
>But as long as infinitely many natnumbers have not left the>
endsegments, they stay inside all of them. And many are the same for
all endsegments. Therefore the intersection of infinite endsegments is
infinite.
Natural numbers don't "leave", sets don't change. You don't 'run out of
indices' or elements to index.
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