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Am Tue, 03 Dec 2024 14:02:05 +0100 schrieb WM:This is an identity: E(1)∩E(2)∩...∩E(n) = E(n).On 03.12.2024 01:32, Jim Burns wrote:This is an equality:On 12/2/2024 9:28 AM, WM wrote:>A quantifier shift tells you (WM) what you (WM) _expect_Here is no quantifier shift but an identity:
but a quantifier shift is untrustworthy.E(1), E(2), E(3), ...
and E(1), E(1)∩E(2), E(1)∩E(2)∩E(3), ...
are identical for every n and in the limit because E(1)∩E(2)∩...∩E(n)
= E(n).
Of course. For endsegments and for their intersection.>That limit being the empty set.No.I cannot read or understand the above. The following is gibberish.
For the set of finite cardinals,
EVEN IF NO END.SEGMENT IS EMPTY,
the intersection of all end segments is empty.⎜ EVEN IF NO END.SEGMENT IS EMPTY,E(1)∩E(2)∩...∩E(n) = E(n).
⎝ the intersection of all end segments is empty.
Sequences which are identical in every term have identical limits.
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