Sujet : Re: Incompleteness of Cantor's enumeration of the rational numbers (extra-ordinary)
De : wolfgang.mueckenheim (at) *nospam* tha.de (WM)
Groupes : sci.mathDate : 06. Dec 2024, 09:59:22
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <viueda$27c49$1@dont-email.me>
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User-Agent : Mozilla Thunderbird
On 05.12.2024 23:29, FromTheRafters wrote:
WM presented the following explanation :
Your answer to Identical sequences have the same limit: "Running with buffaloes does not make one a buffalo" appeared to doubt my claim.
Your example ignores the step-by-step dwindling aspect of the intersections of your infinite sequence of endsegments.
No, it uses this dwindling in endsegments and intersections.
∀n ∈ ℕ: E(1)∩E(2)∩...∩E(n) = E(n)
Identical sequences have identical limits.
Regards, WM