Re: Incompleteness of Cantor's enumeration of the rational numbers (extra-ordinary)

On 06.12.2024 13:23, joes wrote:

Am Thu, 05 Dec 2024 22:31:01 +0100 schrieb WM:

If all natnumbers have been lost, then nothing remains. If there are
infinitely many endsegments, then all contents has become indices.

This happens only in the limit.

It happens in the end. ∀k ∈ ℕ : E(k+1) = E(k) \ {k}.

Two identical sequences have the same limit.
E(1)∩E(2)∩...∩E(n) = E(n).
As long as all endsegments are infinite so is their intersection.

Only as long as you only consider a finite number of them.

As long as all endsegments are infinite, there is no infinite number of them.
Regards, WM