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On 15.12.2024 12:15, joes wrote:Those are all finite.Am Sat, 14 Dec 2024 17:00:43 +0100 schrieb WM:Therefore we use all [1, n].??? The bijection is not finite.Then deal with all infinitely many intervals [1, n].No, we are not forbiding "detailed" analysisThose who try to forbid the detailed analysis are dishonestThat pairs the elements of D with the elements of ℕ. Alas, it canBut we aren't dealing with intervals of [1, n] but of the full set.
be proved that for every interval [1, n] the deficit of hats
amounts to at least 90 %. And beyond all n, there are no further
hats.
swindlers and tricksters and not worth to participate in scientific
discussion.
Wonrg. There is no natural n that „covers N”.With and without limit.Only in the limit.The intervals [1, n] cover the full set.Why can't he? The problem is in the space of the full set, not theThe problem is that you can't GET to "beyond all n" in the pairing,If this is impossible, then also Cantor cannot use all n.
as there are always more n to get to.
finite sub sets.
Even that about infinities.All logic is finite.There is the logic of the infinite.There is no other logic.Nope, it proves it is incompatible with finite logic.Yes, there are only 1/10th as many Black Hats as White Hats, butThis example proves that aleph_0 is nonsense.
since that number is Aleph_0/10, which just happens to also equal
Aleph_0, there is no "deficit" in the set of Natual Numbers.
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