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On 12/24/24 5:53 AM, WM wrote:
They are in bijection. Cantor uses all n, I use all E(n) and therefore all n too. You claimed that I did not. You were wrong.Of course not. There is a bijection {n} <--> E(n). No cardinal number ℵ₀ is involved.the set of E(n), are Aleph_0.Except that both sets, this size of the Natural Numbers and the size of
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