Sujet : Re: because g⤨(g⁻¹(x)) = g(y) [2/2] Re: how
De : ross.a.finlayson (at) *nospam* gmail.com (Ross Finlayson)
Groupes : sci.mathDate : 26. Dec 2024, 20:26:37
Autres entêtes
Message-ID : <XJ2cnZ2xBdB2MPD6nZ2dnZfqnPadnZ2d@giganews.com>
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On 04/19/2024 10:27 AM, Ross Finlayson wrote:
On 04/19/2024 08:15 AM, WM wrote:
Le 19/04/2024 à 00:09, Jim Burns a écrit :
On 4/18/2024 10:54 AM, WM wrote:
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It is enough if you explain
where ω is in the lower line:
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0, 1, 2, 3, ..., ω
| | | | ||| |
0, 2, 4, 6, ..., ω*2
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∀κ < ω: k⋅2 < ω
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That means the space between ω and ω*2 remains empty of poducts 2k, and
not all natural numbers have been doubled because new products have been
inserted below ω.
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∀κ ≥ ω: k⋅2 > ω
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But is it also less than ω*2? Are all products
{ω, ω+1, ω+2, ω+3, ...}*2 less than ω*2?
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Regards, WM
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How about if you consider it a Petri net of two balanced binary trees
pointing at each other in the middle, and a hidden Markov model on the
outside or at each layer, with regards to the structure.
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PN:
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/\
\/
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/\
/\/\
\/\/
\/
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...
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HMM:
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o
o
o
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o
o
o
o
o
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...
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Then, the idea is that where the leaves of the reflective trees
meet, whether that's where also they cross.
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Unboundedly, ....
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