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All FISONs contain all *definable* n.On 12/17/24 4:51 PM, WM wrote:all FISONs contain/are all n.
Hint: For each and every n e IN there is a FISON such that n is in it.Every FISON contains less than half of all natural numbers. Therefore the union of all of them contains less than half of all natural numbers.
BUT there's no FISON such that each and every n e IN is in it.
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