Re: Incompleteness of Cantor's enumeration of the rational numbers (extra-ordinary)

On 28.12.2024 06:23, Moebius wrote:

On 12/17/24 4:51 PM, WM wrote:

 

all FISONs contain/are all n.

Hint: For each and every n e IN there is a FISON such that n is in it.

No. If so, then the union of all FISONs would contain all n.

But fact is
that the union of all FISONs is a FISON (all FISONs have infinitely many
successors) and leaves almost all numbers outside ∀n ∈ ℕ_def: |ℕ \ {1,
2, 3, ..., n}| = ℵo.