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On 1/2/2025 6:31 AM, WM wrote:That is impossible, because all finite ordinals can be subtracted from ℕ without infinitely many remaining. If you don't understand that, it is useless to go on.On 31.12.2024 21:26, Jim Burns wrote:On 12/31/2024 1:20 PM, WM wrote:So it is for each finite.ordinal.>Every union of FISONs which>
stay below a certain threshold
stays below that threshold.
Note: Every FISON stays below 1 % of ℕ.
For each finite ⟦0,j⦆, there are
more.than.#⟦0,j⦆.many finite ⟦0,k⦆
So it is for all definable natural numbers.
Infinitely many can be removed without remainder. But only finitely many can be defined by FISONs.natural numbers which have only few successors... the non.finite.ordinal natural.numbers.
because when they are removed nothing remains
ℕ \ {1, 2, 3, ...} = { } .
We define natural.numbers to be
only finite.ordinals, of which
there are more.than.any.finite.many.
If you want to know how Bob disappears,I know that he never disappears because he is swapped only inside the matrix.
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