Re: Incompleteness of Cantor's enumeration of the rational numbers (extra-ordinary, effectively)

On 03.01.2025 15:49, Richard Damon wrote:

But the members taken collectively *IS* the set.

Yes. The members taken individually are lacking great parts of the set.
∀n ∈ ℕ_def: |ℕ \ {1, 2, 3, ..., n}| = ℵo
ℕ \ {1, 2, 3, ...} = { }
Regards, WM