Re: Incompleteness of Cantor's enumeration of the rational numbers (extra-ordinary, effectively)

On 1/3/25 12:12 PM, WM wrote:

On 03.01.2025 15:49, Richard Damon wrote:
 

But the members taken collectively *IS* the set.

 Yes. The members taken individually are lacking great parts of the set.
∀n ∈ ℕ_def: |ℕ \ {1, 2, 3, ..., n}| = ℵo
ℕ \ {1, 2, 3, ...} = { }
 Regards, WM
 

So you admit tath your logic is just broken.
Your problem is you can't deal with *ALL* the elements at once, as they are in the set.
Sorry, you are just provimg your stupidity.