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On 12.01.2025 20:33, Jim Burns wrote:No it would be the regualar distances in (0, omega), since you excluded omega from the set/interval, and thus is is nothing but the basic infinite set, when when doubled is exactly the same length, infinite.On 1/12/2025 10:54 AM, WM wrote:and that nothing fits between them and ω.No, it depends on completeness.>
It is completely true
that each natural number is a natural number and
that only natural numbers are natural numbers.ℕ is the set of finite ordinals.such than none can be added.
Regular distances in (0, ω) multiplied by 2 remain regular distances in (0, 2ω).
Regards, WM
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