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On 13.01.2025 20:31, Jim Burns wrote:The set of prime number is the same size as N, because we can make a one-to-one mapping between them.On 1/13/2025 12:17 PM, WM wrote:The set of prime numbers is smaller than ℕ but appears infinite too because all sets with more than a definable number of numbers appear infinite.Doubling of all n>
deletes the odd numbers
but cannot change the number of numbers,
ℕ is the set of finite ordinals.
>
There is no finite set larger than ℕ
thus ℕ is infinite.
There is no infinite set smaller than ℕ
No, *YOU* are obviously wrong, and too stupid to understand it.>That is obviously wrong.
𝔼 is the set of even finite ordinals.
There is no finite set larger than 𝔼
thus 𝔼 is infinite
𝔼 ⊆ ℕ
#𝔼 ≤ #ℕ
There is no infinite set smaller than ℕ
#𝔼 ≥ #ℕ
And WM proves his stupdity by not knowing how logic works.In completed infinity all available places are occupied.therefore creates even numbers.>
They do not fit below ω.
No.
They fit below ω
∀n ∈ ℕ: 2n > n. All numbers are doubled. Their number remains the same (not only the cardinality, but the reality). Half of all are deleted. Half are new.
Nope, the problem is your logic doesn't work in the "completed" infinity. I guess you didn't really understand the words you read about it.A step is never from finite to infinite.All that is true in potential infinity, however it is wrong in completed infinity.
Therefore, a step never crosses ω
Therefore, a sum never crosses ω
Therefore, a product never crosses ω
Therefore, a power never crosses ω
Regards, WM
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