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Am Fri, 17 Jan 2025 11:42:02 +0100 schrieb WM:The criterion is not "finite" but "complete".On 17.01.2025 01:37, Richard Damon wrote:On the contrary. Only if you have finitely many, does the "doubling"
>The fact that you think more can be created, just means you neverOnly if we have all of them and can double all of them then by 2n > n
understood how to have all of them in the first place.
greater numbers than all of them are created.
of the elements (not the set) result in larger numbers.
The resultsThat is wrong because for all 2n > n.
might also not be larger than *every* input number.
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