Re: Incompleteness of Cantor's enumeration of the rational numbers (extra-ordinary)

On 1/17/25 7:54 AM, WM wrote:

On 17.01.2025 12:16, joes wrote:

Am Fri, 17 Jan 2025 11:42:02 +0100 schrieb WM:

On 17.01.2025 01:37, Richard Damon wrote:
>

The fact that you think more can be created, just means you never
understood how to have all of them in the first place.

Only if we have all of them and can double all of them then by 2n > n
greater numbers than all of them are created.

On the contrary. Only if you have finitely many, does the "doubling"
of the elements (not the set) result in larger numbers.

 The criterion is not "finite" but "complete".

Right, but you "logic" only hold for finite, and not for the complete infinite set, so is invalid.

 

The results
might also not be larger than *every* input number.
>

That is wrong because for all 2n > n.

Which is irrelvent.

 Regards, WM

All you are doing is proving your utter stupidity, so stupid that you can't recogize your own stupidity and errors.