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Am Sun, 19 Jan 2025 11:47:50 +0100 schrieb WM:
That is possible: ω-1, ω-2, ω-3, ...They contain only natnumbers which have ℵ₀ successors.There are no naturals with a finite number of successors, otherwise
you could count backwards from the end.
But there are always successors if you define the applied naturals individually.If all natural numbers were applied, there would not beThere are no successors if only you would actually "apply" the infinitely
successors: ℕ \ {1, 2, 3, ...} = { }.
many naturals.
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